Integrand size = 36, antiderivative size = 108 \[ \int \frac {(A+B \sin (e+f x)) (c-c \sin (e+f x))^2}{(a+a \sin (e+f x))^2} \, dx=\frac {(A-4 B) c^2 x}{a^2}+\frac {(A-4 B) c^2 \cos (e+f x)}{a^2 f}-\frac {a^2 (A-B) c^2 \cos ^5(e+f x)}{3 f (a+a \sin (e+f x))^4}+\frac {2 (A-4 B) c^2 \cos ^3(e+f x)}{3 f (a+a \sin (e+f x))^2} \]
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Time = 0.19 (sec) , antiderivative size = 108, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.139, Rules used = {3046, 2938, 2759, 2761, 8} \[ \int \frac {(A+B \sin (e+f x)) (c-c \sin (e+f x))^2}{(a+a \sin (e+f x))^2} \, dx=\frac {c^2 (A-4 B) \cos (e+f x)}{a^2 f}-\frac {a^2 c^2 (A-B) \cos ^5(e+f x)}{3 f (a \sin (e+f x)+a)^4}+\frac {c^2 x (A-4 B)}{a^2}+\frac {2 c^2 (A-4 B) \cos ^3(e+f x)}{3 f (a \sin (e+f x)+a)^2} \]
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Rule 8
Rule 2759
Rule 2761
Rule 2938
Rule 3046
Rubi steps \begin{align*} \text {integral}& = \left (a^2 c^2\right ) \int \frac {\cos ^4(e+f x) (A+B \sin (e+f x))}{(a+a \sin (e+f x))^4} \, dx \\ & = -\frac {a^2 (A-B) c^2 \cos ^5(e+f x)}{3 f (a+a \sin (e+f x))^4}-\frac {1}{3} \left (a (A-4 B) c^2\right ) \int \frac {\cos ^4(e+f x)}{(a+a \sin (e+f x))^3} \, dx \\ & = -\frac {a^2 (A-B) c^2 \cos ^5(e+f x)}{3 f (a+a \sin (e+f x))^4}+\frac {2 (A-4 B) c^2 \cos ^3(e+f x)}{3 f (a+a \sin (e+f x))^2}+\frac {\left ((A-4 B) c^2\right ) \int \frac {\cos ^2(e+f x)}{a+a \sin (e+f x)} \, dx}{a} \\ & = \frac {(A-4 B) c^2 \cos (e+f x)}{a^2 f}-\frac {a^2 (A-B) c^2 \cos ^5(e+f x)}{3 f (a+a \sin (e+f x))^4}+\frac {2 (A-4 B) c^2 \cos ^3(e+f x)}{3 f (a+a \sin (e+f x))^2}+\frac {\left ((A-4 B) c^2\right ) \int 1 \, dx}{a^2} \\ & = \frac {(A-4 B) c^2 x}{a^2}+\frac {(A-4 B) c^2 \cos (e+f x)}{a^2 f}-\frac {a^2 (A-B) c^2 \cos ^5(e+f x)}{3 f (a+a \sin (e+f x))^4}+\frac {2 (A-4 B) c^2 \cos ^3(e+f x)}{3 f (a+a \sin (e+f x))^2} \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(234\) vs. \(2(108)=216\).
Time = 11.22 (sec) , antiderivative size = 234, normalized size of antiderivative = 2.17 \[ \int \frac {(A+B \sin (e+f x)) (c-c \sin (e+f x))^2}{(a+a \sin (e+f x))^2} \, dx=\frac {\left (\cos \left (\frac {1}{2} (e+f x)\right )+\sin \left (\frac {1}{2} (e+f x)\right )\right ) \left (8 (A-B) \sin \left (\frac {1}{2} (e+f x)\right )-4 (A-B) \left (\cos \left (\frac {1}{2} (e+f x)\right )+\sin \left (\frac {1}{2} (e+f x)\right )\right )-8 (2 A-5 B) \sin \left (\frac {1}{2} (e+f x)\right ) \left (\cos \left (\frac {1}{2} (e+f x)\right )+\sin \left (\frac {1}{2} (e+f x)\right )\right )^2+3 (A-4 B) (e+f x) \left (\cos \left (\frac {1}{2} (e+f x)\right )+\sin \left (\frac {1}{2} (e+f x)\right )\right )^3-3 B \cos (e+f x) \left (\cos \left (\frac {1}{2} (e+f x)\right )+\sin \left (\frac {1}{2} (e+f x)\right )\right )^3\right ) (c-c \sin (e+f x))^2}{3 a^2 f \left (\cos \left (\frac {1}{2} (e+f x)\right )-\sin \left (\frac {1}{2} (e+f x)\right )\right )^4 (1+\sin (e+f x))^2} \]
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Time = 0.74 (sec) , antiderivative size = 107, normalized size of antiderivative = 0.99
method | result | size |
derivativedivides | \(\frac {2 c^{2} \left (-\frac {-8 A +8 B}{2 \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right )^{2}}-\frac {8 A -8 B}{3 \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right )^{3}}-\frac {4 B}{\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1}-\frac {B}{1+\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )}+\left (A -4 B \right ) \arctan \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )\right )\right )}{f \,a^{2}}\) | \(107\) |
default | \(\frac {2 c^{2} \left (-\frac {-8 A +8 B}{2 \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right )^{2}}-\frac {8 A -8 B}{3 \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right )^{3}}-\frac {4 B}{\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1}-\frac {B}{1+\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )}+\left (A -4 B \right ) \arctan \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )\right )\right )}{f \,a^{2}}\) | \(107\) |
risch | \(\frac {c^{2} x A}{a^{2}}-\frac {4 c^{2} x B}{a^{2}}-\frac {B \,c^{2} {\mathrm e}^{i \left (f x +e \right )}}{2 a^{2} f}-\frac {B \,c^{2} {\mathrm e}^{-i \left (f x +e \right )}}{2 a^{2} f}+\frac {8 i A \,c^{2} {\mathrm e}^{i \left (f x +e \right )}+8 A \,c^{2} {\mathrm e}^{2 i \left (f x +e \right )}-24 i B \,c^{2} {\mathrm e}^{i \left (f x +e \right )}-16 B \,c^{2} {\mathrm e}^{2 i \left (f x +e \right )}-\frac {16 A \,c^{2}}{3}+\frac {40 B \,c^{2}}{3}}{f \,a^{2} \left ({\mathrm e}^{i \left (f x +e \right )}+i\right )^{3}}\) | \(160\) |
parallelrisch | \(\frac {3 c^{2} \left (\left (f x A -4 f x B +\frac {4}{3} A -8 B \right ) \cos \left (\frac {f x}{2}+\frac {e}{2}\right )+\frac {\left (\left (-\frac {11}{6}+4 f x \right ) B -f x A +\frac {4 A}{3}\right ) \cos \left (\frac {3 f x}{2}+\frac {3 e}{2}\right )}{3}+\left (f x A -4 f x B +\frac {4}{3} A -\frac {14}{3} B \right ) \sin \left (\frac {f x}{2}+\frac {e}{2}\right )+\frac {\left (f x A -4 f x B +4 A -\frac {29}{2} B \right ) \sin \left (\frac {3 f x}{2}+\frac {3 e}{2}\right )}{3}+\frac {B \left (\cos \left (\frac {5 f x}{2}+\frac {5 e}{2}\right )-\sin \left (\frac {5 f x}{2}+\frac {5 e}{2}\right )\right )}{6}\right )}{f \,a^{2} \left (3 \cos \left (\frac {f x}{2}+\frac {e}{2}\right )-\cos \left (\frac {3 f x}{2}+\frac {3 e}{2}\right )+\sin \left (\frac {3 f x}{2}+\frac {3 e}{2}\right )+3 \sin \left (\frac {f x}{2}+\frac {e}{2}\right )\right )}\) | \(189\) |
norman | \(\frac {\frac {c^{2} \left (A -4 B \right ) x}{a}+\frac {\left (8 A \,c^{2}-30 B \,c^{2}\right ) \tan \left (\frac {f x}{2}+\frac {e}{2}\right )}{a f}+\frac {c^{2} \left (A -4 B \right ) x \left (\tan ^{9}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{a}+\frac {8 A \,c^{2}-38 B \,c^{2}}{3 a f}-\frac {8 B \,c^{2} \left (\tan ^{8}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{a f}+\frac {2 \left (4 A \,c^{2}-61 B \,c^{2}\right ) \left (\tan ^{6}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{3 a f}+\frac {2 \left (4 A \,c^{2}-35 B \,c^{2}\right ) \left (\tan ^{4}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{a f}+\frac {2 \left (4 A \,c^{2}-25 B \,c^{2}\right ) \left (\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{a f}+\frac {2 \left (4 A \,c^{2}-13 B \,c^{2}\right ) \left (\tan ^{7}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{a f}+\frac {2 \left (12 A \,c^{2}-43 B \,c^{2}\right ) \left (\tan ^{3}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{a f}+\frac {2 \left (12 A \,c^{2}-41 B \,c^{2}\right ) \left (\tan ^{5}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{a f}+\frac {3 c^{2} \left (A -4 B \right ) x \tan \left (\frac {f x}{2}+\frac {e}{2}\right )}{a}+\frac {6 c^{2} \left (A -4 B \right ) x \left (\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{a}+\frac {10 c^{2} \left (A -4 B \right ) x \left (\tan ^{3}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{a}+\frac {12 c^{2} \left (A -4 B \right ) x \left (\tan ^{4}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{a}+\frac {12 c^{2} \left (A -4 B \right ) x \left (\tan ^{5}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{a}+\frac {10 c^{2} \left (A -4 B \right ) x \left (\tan ^{6}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{a}+\frac {6 c^{2} \left (A -4 B \right ) x \left (\tan ^{7}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{a}+\frac {3 c^{2} \left (A -4 B \right ) x \left (\tan ^{8}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{a}}{\left (1+\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )^{3} a \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right )^{3}}\) | \(534\) |
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Leaf count of result is larger than twice the leaf count of optimal. 242 vs. \(2 (104) = 208\).
Time = 0.26 (sec) , antiderivative size = 242, normalized size of antiderivative = 2.24 \[ \int \frac {(A+B \sin (e+f x)) (c-c \sin (e+f x))^2}{(a+a \sin (e+f x))^2} \, dx=-\frac {3 \, B c^{2} \cos \left (f x + e\right )^{3} + 6 \, {\left (A - 4 \, B\right )} c^{2} f x - 4 \, {\left (A - B\right )} c^{2} - {\left (3 \, {\left (A - 4 \, B\right )} c^{2} f x - {\left (8 \, A - 23 \, B\right )} c^{2}\right )} \cos \left (f x + e\right )^{2} + {\left (3 \, {\left (A - 4 \, B\right )} c^{2} f x + 2 \, {\left (2 \, A - 11 \, B\right )} c^{2}\right )} \cos \left (f x + e\right ) + {\left (6 \, {\left (A - 4 \, B\right )} c^{2} f x - 3 \, B c^{2} \cos \left (f x + e\right )^{2} + 4 \, {\left (A - B\right )} c^{2} + {\left (3 \, {\left (A - 4 \, B\right )} c^{2} f x + 2 \, {\left (4 \, A - 13 \, B\right )} c^{2}\right )} \cos \left (f x + e\right )\right )} \sin \left (f x + e\right )}{3 \, {\left (a^{2} f \cos \left (f x + e\right )^{2} - a^{2} f \cos \left (f x + e\right ) - 2 \, a^{2} f - {\left (a^{2} f \cos \left (f x + e\right ) + 2 \, a^{2} f\right )} \sin \left (f x + e\right )\right )}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 2474 vs. \(2 (102) = 204\).
Time = 3.98 (sec) , antiderivative size = 2474, normalized size of antiderivative = 22.91 \[ \int \frac {(A+B \sin (e+f x)) (c-c \sin (e+f x))^2}{(a+a \sin (e+f x))^2} \, dx=\text {Too large to display} \]
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Leaf count of result is larger than twice the leaf count of optimal. 833 vs. \(2 (104) = 208\).
Time = 0.32 (sec) , antiderivative size = 833, normalized size of antiderivative = 7.71 \[ \int \frac {(A+B \sin (e+f x)) (c-c \sin (e+f x))^2}{(a+a \sin (e+f x))^2} \, dx=\text {Too large to display} \]
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Time = 0.33 (sec) , antiderivative size = 130, normalized size of antiderivative = 1.20 \[ \int \frac {(A+B \sin (e+f x)) (c-c \sin (e+f x))^2}{(a+a \sin (e+f x))^2} \, dx=\frac {\frac {3 \, {\left (A c^{2} - 4 \, B c^{2}\right )} {\left (f x + e\right )}}{a^{2}} - \frac {6 \, B c^{2}}{{\left (\tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} + 1\right )} a^{2}} - \frac {8 \, {\left (3 \, B c^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} - 3 \, A c^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + 9 \, B c^{2} \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) - A c^{2} + 4 \, B c^{2}\right )}}{a^{2} {\left (\tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + 1\right )}^{3}}}{3 \, f} \]
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Time = 14.63 (sec) , antiderivative size = 242, normalized size of antiderivative = 2.24 \[ \int \frac {(A+B \sin (e+f x)) (c-c \sin (e+f x))^2}{(a+a \sin (e+f x))^2} \, dx=\frac {\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )\,\left (8\,A\,c^2-30\,B\,c^2\right )+\frac {8\,A\,c^2}{3}-\frac {38\,B\,c^2}{3}+{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^3\,\left (8\,A\,c^2-26\,B\,c^2\right )+{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^2\,\left (\frac {8\,A\,c^2}{3}-\frac {74\,B\,c^2}{3}\right )-8\,B\,c^2\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^4}{f\,\left (a^2\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^5+3\,a^2\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^4+4\,a^2\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^3+4\,a^2\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^2+3\,a^2\,\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )+a^2\right )}+\frac {2\,c^2\,\mathrm {atan}\left (\frac {2\,c^2\,\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )\,\left (A-4\,B\right )}{2\,A\,c^2-8\,B\,c^2}\right )\,\left (A-4\,B\right )}{a^2\,f} \]
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